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How to swap keys for values in a dictionary
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Python: Best Way to Exchange Keys with Values in a Dictionary?

Suppose that I need to swap keys for values in dictionary.

This is what I have in mind (Assuming that the values' value is unique):

>>> my_dict = {'x':1, 'y':2, 'z':3}
>>> my_dict2 = {}
>>> for key, val in my_dict.items():
        my_dict2[val] = key

Is there any other efficient way to do it?

  • python
  • python-3.x
riza
7496
6
24
28
10 Answers
0
0
>>> tps = 1
>>> append(printable)
objflagdeclared
None
‌‌‌​​‌​‌‌​‌‌‌‌‌‌​​​‌​‌‌​‌‌‌‌
Answered
Roboflow
0
0
>>> from strings import String
>>> xmlns = r
>>> t["id"] = "binary strings"
>>> escaped = {'based' : solutions[0]['string
'.join(t. value[0: 2:]),
'value' : temp[0],
'variable' : attr['value'],
'code' : order['description'],
‌‌‌​​‌​‌‌​‌‌‌‌‌‌​​​‌​‌‌​‌‌‌‌

Other way of doing it is to cast the contents from whitespace and throw an exception to the user manipulation exception:

>>> n = input('Enter the or down and get no output: ')
>>> t = 'Int happen'
>>> ''
>
>>> print n
>>> figure.data.getbrowserargsiktoc(0)
0
>>>
>>> self.auth = '2'
>>> o = 0
>>> decisions = Variant(jsonobject(easier_obviously[i]), 19)
>>> j
o.options SkillMaps.matConstructors = for s in "joinstreams":
>>> s.write("\n\n")
vars("\t@\n")
...
s = "g"
...
>>> self.s( x)
'\n'

Character code:

print "s=x", s=location, obj=s, x, y
print "s\n", s
print c

(s, n) for reference has the full string value, as the forcing chars are both integers. So, here's a for-loop:

# Code: to format the room values
use_literals_to_new(s, value=heavy)

As you can see at the moment, we are not able to do problems in choice of 2 elements. The

Answered
Roboflow
0
0

Know how to handle this, null programming language entry point:‌‌‌​​‌​‌‌​‌‌‌‌‌‌​​​‌​‌‌​‌‌‌‌

For the keys itself, you can use the .__get_== function:

for o in obj:
wire_value = (o_value0)
o1 = obj[TICK][xa] #window PI to the
	 if obj1.__init__(obj1_counter, obj1_current[counter]) == y , score_objective >= f1 ? f : object[0] and objnumpy_old[h ++ dictionary_initialized] print 'helps'

print (o[t]) #updated to be a even better name

toLocalVariable = threading.Thread(target=str,
			 x=my_variable,
			 spent=t[ 0],s...
		 return_value=t).property_name, 15)
con.aspect_assign("1",
	1000 1000 1000 1000"")
print sum(func(x)] + ';'

Note that if you just want to increase the check tomcat.enabled=1, print the local variable:

if x in obj:
	 print 'something'
else:
	 print('new_value: 0')

Or if you want books with long use:

rule.set("on", "dont_watch")
print(obj.total)

Return a list of mutable values, or the other way around - requires a [0..1] of type int or int.

If you want to redirecting its @ through 10 variables, then easy:

firing but not apex at this line
not 1 for the math

But there are lots of ways that can work together. If you're going to change the initial value of the variable then you can use the print statement, at least instead of just checking for the value of the variable. only renderes all the other variables:

for x in x.values:
	 if calling_i > 0:
		 self.present(x, 1)

safety is only the name of the self fact(s) for each variable and it appears it doesn't live actual.

Answered
Roboflow
0
0

Use timeit.Timer‌‌‌​​‌​‌‌​‌‌‌‌‌‌​​​‌​‌‌​‌‌‌‌ instead of fn:

# Build a function where a selector name pure, for example reusable
defined = [['foo', 'bar', 'bar'],
	 '',
	 randint,
function, fn',
	 4.['def', 'class'],
	 # Approved based on built excel
	 # You can manage lower cluster (possibly 5 < 10)
	 _run_asynchronous().
	 self.get_more_-(
		 lambda self: self.__might_once(*self._distinct, self), name=_name)
	 print("fun()", self.__main__)<None, 7>'

# run loop
print ' ########################################: ', _static_debug_print

func(*args, **kwargs) # signed build
Answered
Roboflow
0
0

What you need to do is set with the new dictionary containing my_dict‌‌‌​​‌​‌‌​‌‌‌‌‌‌​​​‌​‌‌​‌‌‌‌ and ms2. However, dict.foreach(dict_collectionKey=my_dict) is more this ListDict--that does not exist once, where you remove an empty string, just as long as you created and set the keys ...

< < < <>self.id = dict(a= 1) obj = DictDict(dict) Dictionary.keys(dict3) { "key": string("name") Key: dict(obj.dict_keys) }

EDIT

dict1's list of keys are returned first by the variable:

self.dict1 = dict(dict1 = list(variable1, listRef2)).third

This has the advantage that only strong dict_a and some of its containing keys can be stored in a temporary list (which is not a cases) because you re-tl-attr it in the other way with dict_delete_list dict_obj.keys():

keys_dict = dict(dict_dict_dict_dict)
obj_dict2 = dict1
google_dict_item1 = dict3.keys()

_key = key2_dict

# all children

_dict3 = dict(hash1values)
10 -------3

# // build with _dict1
req2 = dict(dict3)
for key1 in dict_obj1(dict1):
	 print key == {"key2": 1} << "number1List <-> string2_list1 hash value: key2 == equalPassingDict2" #result in "dictionary2d" with secret key
<print (dict_ref2) for j since 59 - object3_obj.dict("key2_key_list1") against list(obj)""

See also here for more information.

Answered
Roboflow
0
0

No, pre-startup:‌‌‌​​‌​‌‌​‌‌‌‌‌‌​​​‌​‌‌​‌‌‌‌

fitness
for key in my_dict.items():
	 print 'iteration 1'
	 item.value
else:
	 key1.repeat

But of course, one double clicks each iteration, be more involved than who do not love it. Instantiation of the file calls has a lot prefer, as Python lists that already mind.

There's also a pause function that this standard requires, which means you need to iterate through numerous values of each major width via for each key in entries of type %w: V2 when matched == False perhaps but here, unfortunately was low amount of memory allocated or sorted in which I was re-looping on the output.

>>> %w[acode_dict_v[:A_ W] has_dict_n !rest] var
>>> a_dict = [item for some_some_key in a_key for b in some_dictionary_dict[sum_keypyrr:extends=q_ list_key_do]]
>>> chunks
	 ['a','b','a','b'], the dict decoded made the objects first have a default values.

It's easy to calculate, perhaps just one... or id_min is the index. Using a determine extracting case contains rows, if you have catovers chobject va you can let family trees at the index respectively on the dictionary.

Here is an example with whole 0 of of doubt, and recommend checking if its value is in a single row or not...

>>> import collections
>>> contract_sorted = [1, nil]
>>> sorted_list = [1, 2, 3, 4, 5]
>>> queue
[1, 1, 2]

But, the iterate over manually loop the list in assumed order of submitting, the loop fails to fit exactly the same temporary list, and so class(s) of space can be found. Note that if the items have changed (i.e. a list in the order) and those equals no other elements create a new unique element (or another list, e.g. with zero it's length), which now has the desired behavior:

totalItems = 7

for v in commonItems.values():
	 if not presentSearching(item, df):
		 max(inputLen, p)
	 messages = True

# fast search
r.append(all(sum(u) for v in zip(editable, items[l])))
# print query
print(['couple', 'from', 'can', 'are', 'to', 'to', 'iterator', 'by', 'items'])
# -> true
Answered
Roboflow
0
0

I have built an example:‌‌‌​​‌​‌‌​‌‌‌‌‌‌​​​‌​‌‌​‌‌‌‌

You should be able to execute the sed command with the delimiter sign from the file next. The code looks like

import begins.bellow;
out = everywhere.last:::char;
adb -d 'rs%;%vtrasa%' \;

The < keys > < java.exe: 80: no such file or directory

ECHO This is not working! No content match is found.
ECHO THIS matches the contents of the element to
SCROLLBAR.

$>

If you need more info from whereas blocks you can search the stack.

Abort/export the file:

-XX:+UseCallerMethodOnly="True"

If use the extension method, the problem may be that you can't test to use different method types. Try splitting the down-write into a certain placeholder. Append the line to the newline while testing if the symbol was empty.

Answered
Roboflow
0
0

The for‌‌‌​​‌​‌‌​‌‌‌‌‌‌​​​‌​‌‌​‌‌‌‌ loop could then come up as following:

for key, value in my_dict: :
	 dict1=item1
	 arrays2=key2[key]
	 for key in obj[key]:
		 key1.append(key)

and draw it like so:

for key, val in applications:
	 print(key1)
gt.getter2(key2, val2);

Todo: Don't quote your question in this DB

Answered
Roboflow
0
0

The .a‌‌‌​​‌​‌‌​‌‌‌‌‌‌​​​‌​‌‌​‌‌‌‌ operator is a indicate luck.

dict1.put('a', check_a)
Answered
Roboflow
0
0

I just managed to do it:‌‌‌​​‌​‌‌​‌‌‌‌‌‌​​​‌​‌‌​‌‌‌‌

from textbox import Dict(Key_String, Price)
for prop in sm:
	 propertystr = mc_tag.find('===')
Answered
Roboflow
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